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puteri [66]
3 years ago
10

Y=.5x+4 Y= -.25x^2+5 Using the quadratic formula, what are the solutions?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Hi there!

\large\boxed{x = -1 \pm \sqrt{5}}

We can solve by setting both equations equal to each other:

.5x + 4 = -.25x² + 5

Move everything to one side:

0 = -.25x² - .5x + 1

Multiply both sides by 4 to cancel out the decimals:

0 = -x² - 2x + 4

Factor out negative from both sides:

0 = x² + 2x - 4

Use the quadratic formula:

\frac{-b \pm \sqrt{b^2-4ac}}{2a}

Plug in the corresponding terms:

x = \frac{-2 \pm \sqrt{4-4(-4)(1)}}{2}

Simplify:

x = \frac{-2 \pm \sqrt{4 + 16}}{2}\\\\x = \frac{-2 \pm \sqrt{20}}{2}

Simplify the radical to reduce:

x = \frac{-2 \pm 2\sqrt{5}}{2}

Divide all terms by 2:

x = -1 \pm \sqrt{5}

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3 years ago
PLEASEEEE
Jobisdone [24]
<h3>Answer:  9.4 feet</h3>

Work Shown:

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3 0
2 years ago
Solve the system using elimination.
KIM [24]
We can't eliminate as is so we have to change something up there in the equations to get either the x values the same number but opposite signs, or the y values the same number but opposite signs.  I chose to change the y values to the same number but different signs. In the first equation y is -3y and in the second one, y is -8y. The LCM of both of those numbers is 24, so we will multiply the first equation by an 8 (8*3=24) and the second equation by 3 (3*8=24) but since they are both negative right now, one of those multiplications has to involve a negative because - * - = +. Set it up like this:
8(-10x - 3y = -18)
-3(-7x - 8y = 11)
Multiply both of those all the way through to get new equations:
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Now the y's cancel each other out leaving only the x's:
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7 0
3 years ago
Read 2 more answers
Find the value of f(12) if f(x)=-2x+4
Contact [7]

Answer:

f(12) = - 20

Step-by-step explanation:

To evaluate f(12), substitute x = 12 into f(x), that is

f(12) = - 2(12) + 4 = - 24 + 4 = - 20

5 0
3 years ago
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