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puteri [66]
3 years ago
10

Y=.5x+4 Y= -.25x^2+5 Using the quadratic formula, what are the solutions?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Hi there!

\large\boxed{x = -1 \pm \sqrt{5}}

We can solve by setting both equations equal to each other:

.5x + 4 = -.25x² + 5

Move everything to one side:

0 = -.25x² - .5x + 1

Multiply both sides by 4 to cancel out the decimals:

0 = -x² - 2x + 4

Factor out negative from both sides:

0 = x² + 2x - 4

Use the quadratic formula:

\frac{-b \pm \sqrt{b^2-4ac}}{2a}

Plug in the corresponding terms:

x = \frac{-2 \pm \sqrt{4-4(-4)(1)}}{2}

Simplify:

x = \frac{-2 \pm \sqrt{4 + 16}}{2}\\\\x = \frac{-2 \pm \sqrt{20}}{2}

Simplify the radical to reduce:

x = \frac{-2 \pm 2\sqrt{5}}{2}

Divide all terms by 2:

x = -1 \pm \sqrt{5}

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