A) 5 to be chosen among a Total : 10 Men + 8 Women
¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five
b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56
So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees
c) 3 Women and 2 Men:
⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M
d) More women than men, it means:
3 W + 2 M OR (we have found it in c) = 2,520)
4 W + 1 M OR ⁸C₄ x ¹⁰C₁ →→→→ = 700
5 W + 0 M OR ⁸C₅ x ¹⁰C₀ →→→→ = 56
Total where W>M = 3,276 groups of 5 where women are at least 3
Net yardage=3-6-4+5=-2
So the team lost 2 yards in four plays...
I don’t know if this is correct: 40%
We have consecutive odd numbers for the sides of a triangle, perimeter 201. We could write an equation, but clearly the middle side is 201/3 = 67, so the other two sides are 65 and 69.
This is almost an equilateral triangle, angles around 60 degrees, so not obtuse, meaning one angle over 90 degrees.
Scalene means the sides are all different lengths; we didn't even have to solve the problem to know this is true.
Smallest side 61, false.
Largest side 69, true.
This last one doesn't make much sense to me. What's a unit here? Dilation of 1/3 means all the linear measures become 1/3 as big, including the perimeter. It would decrease much more than 3 inches, since it would go from 201 inches to 67 inches. If I have to answer I'd go with false.
Answer:
x^4 -x^3 -9x^2 -11x -4
Step-by-step explanation:
We can use the zero product property
(x-a) (x-b) (x-c) (x-d) where a b c d are the roots
(x- -1)(x- -1)(x- -1) ( x-4) since the root -1 is repeated 3 times and 4 is a root
(x+1)(x+1)(x+1) ( x-4)
Foil the first two terms and the last two terms
(x^2 + 2x+1)( x^2 -3x-4)
Foil again
x^4 -3x^3 -4x^2 +2x^3 -6x^2 -8x +x^2 -3x-4
Combine like terms
x^4 -x^3 -9x^2 -11x -4