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Given: ∆ABC≅DEF
Find: BC, BA, m∠D
2 answers:
Answer:
Using CPCTC, we know that congruent parts of the congruent triangles are congruent.
Given: ∆ABC ≅ ∆DEF
BC ≅ FE ⇒ CPCTC. IF FE = 5 (Given), & FE ≅ BC (CPCTC) ∴ BC = 5 (Transitive Property of Equality.)
BA ≅ DE ⇒ CPCTC. IF DE = 11 (Given) & DE ≅ BA (CPCTC) ∴ BA = 11 (Transitive Property of Equality.)
m∠D ≅ m∠A ⇒ CPCTC. Congruent Parts of Congruent Triangles are Congruent. If ∆ABC ≅ ∆DEF (given), then through CPCTC, m∠D ≅ m∠A.
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Answer:
BC = 5
BA11
angle D = 27
Step-by-step explanation:
If the triangles are similar
ABC ≅ DEF
That means AB ≅ DE
BC ≅ EF
and CA ≅ FD
We want to find AB so it is equal to DE
BC = EF = 5
BA = AB = DE =11
We also know the angles are equal
A = D
B = E
C = F
Angle A = angle D = 27
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