Answer:
x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Step-by-step explanation:
1−2sin2 x≤−sin x ⇒ (2sin x+1)(sin x−1)≥0
sin x≤−1/2 or sin x≥1
−5π/6+2nπ≤x≤−π/6+2nπ or , n ϵ I x=(4n+1)π/2, n ϵ I⇒ -5π6+2nπ≤x≤-π6+2nπ or , n ϵ I x=4n+1π2, n ϵ I (as sin x = 1 is valid only)
In general⇒ In general x∈[2nπ−5π/6, 2nπ−π/6]∪{(4n+1)π/2}, n ϵ I
Answer:
v = -8i - 6j
Step-by-step explanation:
The starting point is (9, 9)
The direction of the vector is the direction of the arrowhead.
The i is the horizontal component.
The j is the vertical component.
Therefore, to go from the start to the end of the line, we need to travel negative 8 units (horizontally) and negative 6 units (vertically).
Therefore, v = -8i - 6j
Answer: * =times\multiplication
<h2>
<u>every month the amount of money increases by a factor of 1.01</u></h2>
Explanation:
when t is 0 M(t) is 1000
when t is 1 M(t) is 1000 times 1.01
when t is 2 M(t) is 1000 times 1.01 squared which also looks like this:
1000* 1.01* 1.01
so in the end the factor is 1.01 because that is what is getting added each month (each month another 1.01 appears)
Answer:
2.7 x 5-6
Step-by-step explanation:
Answer:
-3/5
Step-by-step explanation:
Start at 1/5 then go 4 to the left
