Answer:
<h3>The surface area in square meters that Darren has to paint is
</h3><h3>∴
</h3>
Step-by-step explanation:
Given that Darren is painting a wooden block is a rectangular prism
Its length is 12 cm ,width is 9 cm and height is 5 cm
<h3>To find the surface area in square meters that Darren has to paint :</h3>
Let l be the length, w be the width and h be the height
Then l=12 cm , w=9 cm and h=5 cm
The formula for the Surface area is
A=2(lw+wh+hl) square units
Substitute the values in formula we get,
A=2(12(9)+9(5)+5(12))
=2(108+45+60)
=2(213)
=426
<h3>∴
</h3><h3>∴ the surface area in square meters that Darren has to paint is
</h3>
Answer:
18.9
Step-by-step explanation:
First, lets solve for the fractions. You can divide the fractions from the top, to their bottom (4 divided by 5, 3 divided by 5), in this case, you get 1.4. Now you have to rewrite the problem: 1.4+3.5x5. You solve it, and get 18.9.
Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
Answer:
Step-by-step explanation:
We are asked the equation of the graph which passes through the points at (0,5) and (-3,-4).
Now, we know that the equation of a straight line passing through the points (
) and (
) is given by
.
So, in our case () ≡ (0,5) and () ≡ (-3,-4)
Therefore, the equation of the straight line will be
⇒ 
⇒ (Answer)
Answer:
30000 times larger.
Step-by-step explanation:
10^7 * 9/10^3*3
Law of exponents cancel some of the tens.
10^4 * 9/3
Cancel out the three.
10^4 *3
Compute
30000 times larger.
