The absolute value for 2x+3=11 is x=4
2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
Answer:
2.67
Step-by-step explanation:
sorry if this is wrong i did this in my head :(
128 degrees I hope this helped you
Answer:
3.4
Step-by-step explanation:
(−9 + 6.8 − 1.2) · (−0.49 − 0.51)
(−3.4) · (−1)
3.4