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lesantik [10]
3 years ago
12

Lexie earned $64.38 for working from 8:00 AM to 4:15 PM. Within that time, she took a 1 hour lunch break for which she did not g

et paid. How much does Lexie earn per hour?
Mathematics
2 answers:
melamori03 [73]3 years ago
7 0
There are 8 hours and 15 minutes in her work day. If you take off one of those hours, it would be 7 hours and 15 minutes. If she is getting paid by the hour, you can take off the 15 minutes since it doesn't matter. Then, you divide her income ($64.38) by her hours (7). From this, you get about $9 (or if you wanna be specific, $9.20) per hour.
SCORPION-xisa [38]3 years ago
3 0
$8.88 per hour is the answer
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The rectangular field is 120 yards long and 40 yards wide. How many square yards is it’s area?
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Answer:

4800 yards wide

Step-by-step explanation:

120 x 40=4800

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Which expression is equivalent to 108 - 58 + 8 + 69 +47
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Answer:

5f+6g+12

Step-by-step explanation:

Combine like terms

10f-5f = 5f

6g

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5f+6g+12

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Read 2 more answers
Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe
valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right)  is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3

(a)

(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

(x+1)(x-1)=x^{2}-1^{2}\\

we can say that this is neither sum  nor difference of cube as it's difference of squares.

(d)

(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)

by comparison with formula this is equal to

x^{3}+4^{3}\\

Hence this is sum of cubes

(e)

(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)

by comparison with formula we can say that this is neither sum  nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right) is sum of cubes

To know more about cubes visit: brainly.com/question/107100

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