Answer:
Step-by-step explanation:
Suppose we think of an alphabet X to be the Event of the evidence.
Also, if Y be the Event of cheating; &
Y' be the Event of not involved in cheating
From the given information:



Thus, 
P(Y') = 1 - 0.01
P(Y') = 0.99
The probability of cheating & the evidence is present is = P(YX)



The probabilities of not involved in cheating & the evidence are present is:


(b)
The required probability that the evidence is present is:
P(YX or Y'X) = 0.006 + 0.000099
P(YX or Y'X) = 0.006099
(c)
The required probability that (S) cheat provided the evidence being present is:
Using Bayes Theorem



Answer:
add one please i wanna help!
Step-by-step explanation:
It will be equivalent to (5y+9)
hope i was able to help and i wasn’t to late.
I hope this helps you
A=1/2.b.h
given Area is 24 and base is 8
24=1/2.8.h
24=4.h (divide 4 both of sides)
h=6 (height)
Wednesday it’s 5 degrees all the others are lower