F(103)=103/103+9
103/103=1
so f(103)=1+9
THE ANSWER IS 10 :)
P square=P triangle equilateral
4(x+2)=3*2x
4x+4*2=6x
4x+8=6x
6x-4x=8
2x=8
x=8/2
x=4
I need to know the dimensions to solve. Ex: "Line AC is 2.5 centimeters"
My bad - should've asked that under "Ask For Details."
Sorry :(
Solve the following system using elimination:
{-2 x + 2 y + 3 z = 0 | (equation 1)
{-2 x - y + z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)
Subtract equation 1 from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x - 3 y - 2 z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)
Multiply equation 2 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+3 y + 2 z = 3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)
Add equation 1 to equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+3 y + 2 z = 3 | (equation 2)
{0 x+5 y + 6 z = 5 | (equation 3)
Swap equation 2 with equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+3 y + 2 z = 3 | (equation 3)
Subtract 3/5 × (equation 2) from equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - (8 z)/5 = 0 | (equation 3)
Multiply equation 3 by 5/8:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - z = 0 | (equation 3)
Multiply equation 3 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)
Subtract 6 × (equation 3) from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y+0 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)
Divide equation 2 by 5:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)
Subtract 2 × (equation 2) from equation 1:
{-(2 x) + 0 y+3 z = -2 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
v0 x+0 y+z = 0 | (equation 3)
Subtract 3 × (equation 3) from equation 1:
{-(2 x)+0 y+0 z = -2 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)
Divide equation 1 by -2:
{x+0 y+0 z = 1 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)
Collect results:
Answer: {x = 1, y = 1, z = 0
Answer:
Explanation:
1)<u> Principal quantum number, n = 2</u>
- n is the principal quantum number and indicates the main energy level.
<u>2) Second quantum number, ℓ</u>
- The second quantum number, ℓ, is named, Azimuthal quantum number.
The possible values of ℓ are from 0 to n - 1.
Hence, since n = 2, there are two possible values for ℓ: 0, and 1.
This gives you two shapes for the orbitals: 0 corresponds to "s" orbitals, and 1 corresponds to "p" orbitals.
<u>3) Third quantum number, mℓ</u>
- The third quantum number, mℓ, is named magnetic quantum number.
The possible values for mℓ are from - ℓ to + ℓ.
Hence, the poosible values for mℓ when n = 2 are:
- for ℓ = 1, mℓ = -1, 0, or +1.
<u>4) Fourth quantum number, ms.</u>
- This is the spin number and it can be either +1/2 or -1/2.
Therfore the full set of possible states (different quantum number for a given atom) for n = 2 is:
- (2, 0, 0 +1/2)
- (2, 0, 0, -1/2)
- (2, 1, - 1, + 1/2)
- (2, 1, -1, -1/2)
- (2, 1, 0, +1/2)
- (2, 1, 0, -1/2)
- (2, 1, 1, +1/2)
- (2, 1, 1, -1/2)
That is a total of <u>8 different possible states</u>, which is the answer for the question.
