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Elodia [21]
3 years ago
5

2. Trapezoid WXYZ is located at W(2.1) X[3.

Mathematics
1 answer:
Nataliya [291]3 years ago
5 0

Point Y is (6, -1)

Subtract 6 from the y coordinate in point y since it is translated down. keep the x coordinate since it is only being translated up and down, or by the y axis

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The constant of proportionality is $1.5 per jar of sauce. Hope it help!
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You measure 47 backpacks' weights, and find they have a mean weight of 79 ounces. Assume the population standard deviation is 13
ki77a [65]

Answer:

3.14

Step-by-step explanation:

Given that:

Mean weight (m) = 79 ounces

Population standard deviation (s) = 13.1

Sample size = 47

Maximal margin of error associated with 90% confidence interval.

The margin of error is given by:

Zcritical * (standard deviation / sqrt(sample size)

Z critical at 90% confidence interval = 1.645

Hence,

Zcritical * (standard deviation / sqrt(sample size)

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1.645 * (13.1 / 6.8556546)

1.645 * 1.9108313

Hence, the margin of error is :

3.1433174885

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8 0
3 years ago
A conical paper cup has a radius of 2 inches. Approximate, to the nearest degree, the angle β (see the figure) so that the cone
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V = \frac{1}{3} \pi r^{2} h

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F(x) = 3x2 - 11<br> Find f(-5)
Over [174]
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6 0
3 years ago
A rectangle is placed around a semicircle as shown below. The length of the rectangle is 14mm. Find the area of the shaded regio
Damm [24]

Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

7 0
3 years ago
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