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Alex_Xolod [135]
3 years ago
15

You measure 47 backpacks' weights, and find they have a mean weight of 79 ounces. Assume the population standard deviation is 13

.1 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean backpack weight.
Give your answer as a decimal, to two places
Mathematics
1 answer:
ki77a [65]3 years ago
8 0

Answer:

3.14

Step-by-step explanation:

Given that:

Mean weight (m) = 79 ounces

Population standard deviation (s) = 13.1

Sample size = 47

Maximal margin of error associated with 90% confidence interval.

The margin of error is given by:

Zcritical * (standard deviation / sqrt(sample size)

Z critical at 90% confidence interval = 1.645

Hence,

Zcritical * (standard deviation / sqrt(sample size)

1.645 * 13.1 / sqrt(47)

1.645 * (13.1 / 6.8556546)

1.645 * 1.9108313

Hence, the margin of error is :

3.1433174885

= 3.14

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fredd [130]

Answer:

The answer is D

Step-by-step explanation:

4+(-8+24)=20

4+(16)=20

20=20

5 0
4 years ago
Rachel has 10 sweets in a bag.
LenKa [72]

Using it's concept, it is found that there is a 0.713 = 71.3% probability that Rachel takes no more than three sweets from the bag.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, we have that:

  • One sweet, the probability is 3/10.
  • For two, the probability is 7/10 then 3/9.
  • For three, it is 7/10 then 6/9 then 3/8.

So:

p = \frac{3}{10} + \frac{7}{10} \times \frac{3}{9} + \frac{7}{10} \times \frac{6}{9} \times \frac{3}{8} = 0.713

0.713 = 71.3% probability that Rachel takes no more than three sweets from the bag.

More can be learned about the probabilities at brainly.com/question/24826394

7 0
2 years ago
PLEASE EXPLAIN...WILL MARK BRAINLIEST FOR BEST ANSWER
Ira Lisetskai [31]

Answer:

  • a(x) = 20 + 0.60x
  • domain [0, 50]; range [20, 50]
  • maybe

Step-by-step explanation:

a) If x liters are removed from a container with a volume of 50 L, the amount remaining in the container is (50 -x) liters. Of that amount, 40% is acid, so the acid in the container before any more is added will be ...

  0.40 × (50 -x)

The x liters are replaced with 100% acid, so the amount of acid that was added to the container is ...

  1.00 × (x)

Then after the remove/replace operation, the total amount of acid in the container is ...

  a(x) = 0.40(50 -x) +1.00(x)

  a(x) = 20 +0.60x . . . . . liters of acid in the final mixture

__

b) The quantity removed cannot be less than zero, nor can it be more than 50 liters. The useful domain of the function is 0 ≤ x ≤ 50. (liters)

The associated range is 20 ≤ a ≤ 50. (liters)

__

c) As we found in part b, the amount of acid in the final mixture may range from 20 liters to 50 liters. So, the percentage of acid in the final mix will range from 20/50 = 40% to 50/50 = 100%. The mixture could be 50% acid, but is not necessarily.

5 0
3 years ago
What is the final step in solving the inequality –2(5 – 4x) &lt; 6x – 4?
Akimi4 [234]

Answer:

–2(5 – 4x) < 6x – 4

<=>

-10 + 8x < 6x - 4

<=>

2x < 6

<=>

x < 3

Hope this helps!

:)

8 0
3 years ago
You put $400 in a savings account. The account earns 2% simple interest per year. a. What is the interest earned after 6 years?
Vikki [24]
I think you go
400(.02)(6)=48
400+48=448
I believe this is the answer.
6 0
3 years ago
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