1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
3 years ago
7

3)

Mathematics
2 answers:
Setler [38]3 years ago
8 0
Answer is 7.6 to the question
Sindrei [870]3 years ago
5 0

Answer:

7.6 liters

Step-by-step explanation:

You might be interested in
Ramon makes nectar for a hummingbird feeder by mixing 8 cups of water with 2 cups of sugar. Tiffany makes nectar by mixing 9 cup
cluponka [151]

Answer:

Tiffany

Step-by-step explanation:

Ramon is 4 to 1 water to sugar

Tiffany is 3 to 1 water to sugar

4 0
2 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Which of the following is a measure of variation for a numerical data set ? Plz help
kipiarov [429]
I’m pretty sure it would be interquartile range, since range is the measure that measures variation within a data set.
5 0
3 years ago
..................................................................................
Jobisdone [24]

Answer:

7

Step-by-step explanation:

7 0
2 years ago
If the function f(x)=2x-3 and g(x)= 3/2x + 1 which is a tru statement?
Sunny_sXe [5.5K]

Answer: 3 f(8)=g(8)

Step-by-step explanation:

2(8)-3=3/2(8)+1

16-3=12+1

13=13

6 0
2 years ago
Read 2 more answers
Other questions:
  • Which components are a possible representation of vector u if ||-4u|| ≈ 14.42?
    14·1 answer
  • A disadvantage of privately owned media is its __________.
    14·1 answer
  • Find the sum or difference write the answer in simplest form 3/10 4/10=
    6·1 answer
  • a fish tank in the shape of a rectangular prism measures 100 x 60 x 40/The water level reached the midpost of the base (50cm mar
    15·1 answer
  • If a quadrilateral has three angles measuring 60',45' and 100' what is the angle of the fourth angle​
    14·1 answer
  • -3(2x+7)=-51 what does x=
    8·1 answer
  • . Which function's graph has a vertex at (-1, -3) and contains the point (2, 15)?<br> HELPPP PLEASEE
    6·1 answer
  • Find the value of x please help<br>Will give brainliest​
    15·1 answer
  • Rosa's family wants to switch cell phone plans. Cloud Line Cell Service is offering a one-time discount of $25 for families that
    8·1 answer
  • A triangle has a base length of 2ac2 and a height 6 centimeters more than the base length. Find the area of the triangle if a =
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!