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2 years ago

Khan academy how to solve equations with fractions and mixed numbers

1 answer:

8 0

Generally, you are told to approach these by "clearing fractions". That is, you generally multiply the equations by the least common denominator so all fractions and mixed numbers become integers.

Alternatively, you can simply do the arithmetic using the numbers given. You learned a long time ago how to add, subtract, multiply, and divide mixed numbers and fractions. Do these operations as necessary to solve the equations.

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Mark A machine has two parts labeled A and B. The probability that part A works for one year is 0.8 and the probability that par

Mrrafil [7]

Answer:

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.

This means that $P(A) = 0.8, P(B) = 0.6$

The probability that at least one part works for one year is 0.9.

This means that: $P(A \cup B) = 0.9$

We also have that:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$0.9 = 0.8+0.6 - P(A \cap B)$

$P(A \cap B) = 0.5$

Calculate the probability that part B works for one year, given that part A works for one year.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.5}{0.8} = 0.625$

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

3 0

2 years ago

Find the range for f(x) = x^2 1, for x < 0. y ≥ 1 y > 1 y < 1 y ≤ 1

Rus_ich [418]

For x < 0, range is y ≤ 1.

3 0

3 years ago

Identify the slope and y-intercept y = -2/3x -3 m = b =

givi [52]

Answer:

m=-2/3 b=-3

Step-by-step explanation:

6 0

2 years ago

Mr. Smith is paid $9. 50 per hour for fixing watches. Write an expression for the amount of money Mr. Smith earns in h hours. In

IrinaK [193]

Answer:

$9.50h, $(9.50h +2.20rh)

Step-by-step explanation:

Every hour ----- $9.50

h hours ----- h ×$9.50

Amount of money Mr Smith earns in h hours

= $9.50h

If he fixes a watch per hour, additional income= $2.20h

If he fixes r watches per hour, additional income= $2.20rh

Total income

= $(9.50h +2.20rh)

5 0

2 years ago

One of the factors of 34 is chosen at random. What is the probability that the factor is itself a two digit number?

solong [7]

A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?

The positive whole-number factors of 30 are:

1, 2, 3, 5, 6, 10, 15 and 30.

So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that

P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors

=38=3×.125=.375

8 0

2 years ago