Answer:
Step-by-step explanation:
Let the number of dimes be d and quarters be q
<u>The value is $8.80 = 880¢, so:</u>
- 10d + 25q = 880 ⇒ 2d + 5q = 176
<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>
- 25d + 10q = 730 ⇒ 5d + 2q = 146
<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>
- 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
- 4d - 25d = -378
- -21d = -378
- d = -378/-21
- d = 18
Answer:
c. y=56(2)x-1 sorry if its wrong
Answer:
6x+15
Step-by-step explanation:
Answer:
Where,
x: he number of tickets sold
y: the amount of money collected for the tickets
The domain of the function must be:
Therefore, we must find a table that complies with this restriction and also have the corresponding values for x and y.
The first table complies with the restriction and has correct values for the variables:
x y
0 0
10 50
51 255
400 2000
Answer:
x=2, y=1. (2, 1).
Step-by-step explanation:
x=2y
2x+5y=9
-------------
2(2y)+5y=9
4y+5y=9
9y=9
y=9/9
y=1
x=2(1)=2
