is simply the difference of both amounts, but firstly let's convert the mixed fractions to improper, and subtract.
![\bf \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\\\ \stackrel{mixed}{6\frac{7}{16}}\implies \cfrac{6\cdot 16+7}{16}\implies \stackrel{improper}{\cfrac{103}{16}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Jessie}{\cfrac{103}{16}}-\stackrel{Bryce}{\cfrac{9}{2}}\implies \stackrel{\textit{our LCD is 16}}{\cfrac{(1)103-(8)9}{16}}\implies \cfrac{103-72}{16}\implies \cfrac{31}{16}\implies 1\frac{15}{16}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B4%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B9%7D%7B2%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7Bmixed%7D%7B6%5Cfrac%7B7%7D%7B16%7D%7D%5Cimplies%20%5Ccfrac%7B6%5Ccdot%2016%2B7%7D%7B16%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B103%7D%7B16%7D%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Cstackrel%7BJessie%7D%7B%5Ccfrac%7B103%7D%7B16%7D%7D-%5Cstackrel%7BBryce%7D%7B%5Ccfrac%7B9%7D%7B2%7D%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bour%20LCD%20is%2016%7D%7D%7B%5Ccfrac%7B%281%29103-%288%299%7D%7B16%7D%7D%5Cimplies%20%5Ccfrac%7B103-72%7D%7B16%7D%5Cimplies%20%5Ccfrac%7B31%7D%7B16%7D%5Cimplies%201%5Cfrac%7B15%7D%7B16%7D)
Answer:
3 9/10,64,B,D
Step-by-step explanation:
Answer:
295/72
Step-by-step explanation:
Answer:
SAS, SSS, AAA
Step-by-step explanation:
Because Im bored X D
<span>Alright, here's your answer.
y-intercept is computed (not found) by assigning x = 0 and computing y: here that is f(0) = Log(2*0 + 1) – 1 = Log(1) – 1 = 0 – 1 = -1
y-intercept is (0, -1)
x-intercept is computed by solving f(x) = 0 for x: here that is
0 = Log(2x + 1) – 1 → 1 = Log(2x + 1)
Assuming the Log cited is base 10, then 10^1 = 10^Log(2x + 1) = 2x + 1
That’s 10 = 2x + 1
Therefore 9 = 2x
x = 9/2 = 4.5
Check this result in the original equation, I did!
Your answer is - x-intercept is (4.5, 0)
I hope I helped! :)
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