Given: <span>y = x^2 + 6x - 5. Then a = 1, b = 6 and c = -5.
The x-coord. of the vertex is given by x = -b / (2a), which here is x = -6 / (2*1) = -3.
Use the given formula </span><span>y = x^2 + 6x - 5 to find the value of y when x = -3:
y = (-3)^2 + 6(-3) - 5 = 9 - 18 - 5 = -14
Then the vertex is (-3, -14).</span>
Answer:
If you were to fully simplify it would technically be 1/2 as 4/8 is correct but can be further rounded down
Step-by-step explanation:
1/8 x 4 = 4/8
4/8 ÷ 4 = 1/2
To Find :-
- The algebraic equations to solve the above problem .
Solution :-
Let ,
- Large number = L
- Small number = S
— According to first statement ,
— According to second statement ,
- 3L + 4S = 54
- 3L + 4S - 54 = 0 .
These equations matches with the second option b .
Option b is the correct answer.
F(-5) = 6(-5)^3 + 24(-5)^2 - 24(-5) + 5 = 0
so x = -5 is one zero.
Answer:
vertical asymptote at x = 2
Step-by-step explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.
3x - 6 = 0 ⇒ x = 2 ← is the vertical asymptote