Answer:
125feet
Step-by-step explanation:
Given the equation that modeled the height expressed as h = -16t^2 + 80t + 25, where h is the height and t is the time in seconds.
The arrow reaches the maximum height at dh/dt = 0
dh/dt = -32t + 80
0= -32t+80
32t = 80
t = 80/32
t = 2.5secs
substitute t = 2.5 into the formula;
h = -16t^2 + 80t + 25
h = -16(2.5)^2 + 80(2.5) + 25
h = -16(6.25)+225
h = -100+225
h = 125
Hence the maximum height the arrow reaches is 125feet
Answer:
any coordinate outside the parabola is a reasonable answer.
Step-by-step explanation:
test the solution (0, 0) and if if that number is greater than 0 then the rest of the points outside on the inside are.
x = 0
y = 0
(0)^2 - 2(0) - 3 = -3
-3 is less than 0 so (0, 0) is not a possibility so any coordinate outside the parabola is a reasonable answer.
V = π r² h
V= π (4x+2)² (5x+4)
V = π (4x+2)(4x+2)(5x+4)
V = π (16x²+16x+4)(5x+4)
V= π(80x³+144x²+84x+16)
V= 251.33x³ +452.39x²+263.89x+50.27
Answer: the answer is an equation
Step-by-step explanation:
