2x + 5y = -8 . . . (1)
-133x - 4y = -8 . . . (2)

(1) * 4 => 8x + 20y = -32 . . . (3)
(2) * -5 => -665x + 20y = 32 . . . (4)

(3) - (4) => 673x = 0
x = 0
From (1), 2(0) + 5y = -8
5y = -8
y = -8/5

3 0

3 years ago

How do you complete the square to rewrite y= x^ -6x + 15 in vertex form

Vaselesa [24]

Vertex form of a quadratic equation is $y=a(x-h)^{2}+k$
where (h, k) is the vertex.

Our aim is to write the expression $y=x^{2} -6x+15$ in the form
$y=a(x-h)^{2}+k$

$y=x^{2} -6x+15$

$y=x^{2} -2*3*x+15$

$y=(x^{2} -2*3*x+ 3^{2})-3^{2}+ 15$

$y=(x-3)^{2}-9+15$

$y=(x-3)^{2}+6$

5 0

3 years ago

Find the distance between the points. (-4,2), (-4,-5) The distance is _ .

MaRussiya [10]

Answer:

The distance is (-4,3)

Step-by-step explanation:

count between the numbers :)

4 0

3 years ago

Read 2 more answers

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nirvana33 [79]

Answer:

Is this a question or..........

Step-by-step explanation:

5 0

3 years ago