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Elenna [48]
3 years ago
8

Find the distance between the points. (-4,2), (-4,-5) The distance is _ .

Mathematics
2 answers:
MaRussiya [10]3 years ago
4 0

Answer:

The distance is (-4,3)

Step-by-step explanation:

count between the numbers :)

Allushta [10]3 years ago
3 0

Answer:

distance = 7 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (- 4, 2 ) and (x₂, y₂ ) = (- 4, - 5 )

d = \sqrt{(-4-(-4))^2+(-5-2)^2}

   = \sqrt{(-4+4)^2+(-7)^2}

   = \sqrt{0^2+49}

   = \sqrt{49}

   = 7

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The graph below shows a company's profit f(x), in dollars, depending on the price of pens x, in dollars, sold by the company:
Volgvan

The answers to the various part as well as its reasons are given below

<h3 /><h3>Part A:</h3>
  • The x-intercepts shows a zero profit.
  • The maximum value of the graph tells  or depict the maximum profit.
  • The function is one that goes up or increases upward until it reach the vertex and then it falls or decreases after it.
  • This implies that the profit goes up as it reaches the peak at the vertex and it goes down after the vertex up until it gets to zero.
  • The  profits are negative as seen on the left of the first zero and on the right of the second zero.

<h3>Part B:</h3>

An approximate average rate of change of the graph from x = 3 to x = 5, shows the reduction in profit from  3 to 5.

<h3>Part C:</h3>

Based on the above,  the domain is one that is held back or constrained by x = 0 .

We are compelled at x = 6 due to the fact that we have to maneuver a negative profit.

Learn more about quadratic function from

brainly.com/question/25841119

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4 0
2 years ago
write a quadratic function in vertex form whose graph has the vertex (1,0) and passes through point (2,-17)
kobusy [5.1K]

Answer:

\displaystyle f(x) = -17(x-1)^2

Step-by-step explanation:

We want to write a quadratic function in vertex form whose vertex is (1, 0) and passes through the point (2, -17).

Recall that vertex form is given by:

\displaystyle f(x) = a(x-h)^2 + k

Where (<em>h</em>, <em>k</em>) is the vertex and <em>a</em> is the leading coefficient.

Since our vertex is at (1, 0), <em>h</em> = 1 and <em>k</em> = 0:

\displaystyle f(x) = a(x-1)^2

It passes through the point (2, -17). Hence, when <em>x</em> = 2, <em>y</em> = -17:

\displaystyle (-17) = a((2)-1)^2

Solve for <em>a: </em>

<em />\displaystyle a = -17<em />

<em />

In conclusion, our quadratic function in vertex form is:

\displaystyle f(x) = -17(x-1)^2

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