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dsp73
3 years ago
15

Please help I need help on this

Mathematics
1 answer:
natulia [17]3 years ago
7 0

Answer: the answer is 120 for it the area but that is not on the answer list.

Step-by-step explanation:

You might be interested in
Determine which line is perpendicular to y = - 7/5x-2.​
tatuchka [14]

Answer:

y = 5/7 x  - 6

Step-by-step explanation:

For two lines to be perpendicular, the product of their slope must be -1

The slope of the given function is -7/5

Let the slope of the required function be m

m * -7/5 = -1

7/5 m = 1

7 = 5m

m = 5/7

The slope of the line perpendicular to the line is 5/7

The required equation (using any value of the y-intercept) is expressed as;

y = 5/7 x  - 6

Note that the y-intercept value was assumed and any value can be used

6 0
2 years ago
Write an arithmetic expression that calculates the average of 18 and 46. you may already know that: the average of two numbers i
Masteriza [31]

In this question , we have to write an arithmetic expression that calculates the average of 18 and 46.

TO find the average, we have to add the numbers and divide by 2.

So here we have to add 18 and 46 and divide by 2, that is

d = \frac{18+46}{2} = \frac{64}{2}

And that's the required algebraic expression .

8 0
3 years ago
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
Find the mode for the following distribution.
goldfiish [28.3K]

Answer:

24

Step-by-step explanation:

mode means most so 24 is written twice and the others only once.

you're welcome if I helped. :/ (not sure if I helped)

7 0
2 years ago
I dont get this ............
Karo-lina-s [1.5K]

Answer:

i think these inequalities shows B

6 0
3 years ago
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