Answer:
isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.
Step-by-step explanation:
Let 
denote a set of elements. 
would denote the set of all ordered pairs of elements of 
.
For example, with 
, 
and 
are both members of . However, 
because the pairs are ordered.
A relation on is a subset of . For any two elements
, 
if and only if the ordered pair 
is in 
.
A relation on set is an equivalence relation if it satisfies the following:
- Reflexivity: for any
, the relation needs to ensure that 
(that is: 
.)
- Symmetry: for any , if and only if
. In other words, either both and 
are in , or neither is in .
- Transitivity: for any
, if and 
, then 
. In other words, if and 
are both in , then 
also needs to be in .
The relation (on ) in this question is indeed reflexive. 
, 
, and 
(one pair for each element of ) are all elements of .
isn't symmetric. 
but 
(the pairs in 
are all ordered.) In other words, 
isn't equivalent to 
under even though 
.
Neither is transitive. 
and 
. However, . In other words, under relation , 
and 
does not imply 
.
Answer:
2/5 of 3 = 2/5 * 3 = 6/5....what he plants
(6/5) / 5 = 6/5 * 1/5 = 6/25 <== what each friend got
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. Shifting 
right or left, top or down, as the graph in the question has the same illustration of . Consider
2. find a and b by using two sample points from the graph: 
and 
| 1 2 ||x| = |4| - | 3 -1 ||y| |6| <span>-3 | 1 2||x| = |4| </span>
<span>| 3 -1||y| |6| </span>
<span>|-3 -6||x| = |-12| </span>
<span>| 3 -1||y| |6 | </span>
<span>| 0 -7 ||x| = | -6 | </span>
<span>| 3 -1 ||y| | 6 | </span>
<span>y = 6/7 </span>
<span>x = 16/7</span>
