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3 years ago

15

Patty's Party Store mixes almonds and cashews in their Gourmet Mix in a ratio of 6 to 5. If one batch of this mix has 18 ounces

of almonds, how many ounces of cashews does it have?

1 answer:

Lunna [17]3 years ago

3 0

click and follow https://twitch.tv/kamyoman

Step-by-step explanation:

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There are 16 girls and 18 boys in a class. The teacher Chooses a students name at random to answer a question. What is the proba

murzikaleks [220]

Step-by-step explanation:

girl=16

boy=18

picking a girl at random

the answer is = 1/16

6 0

3 years ago

A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo

djverab [1.8K]

Answer:

a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) $31690.7 g/L$

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

Then we have, $R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}$ , and

$R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}$

So we obtain. $\frac{dy}{dt}=4000-\frac{2y}{25}$ , then

$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) The tank will overflow due Rin>Rout, at a rate of $80 L/min-40L/min=40L/min$ , due we have 500 L to overflow $\frac{500L}{40L/min} =\frac{25}{2} min=t$ , so we can evualuate the expression of a) $y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7$ , is the salt concentration when the tank overflows

4 0

3 years ago

Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate

Harman [31]

Answer:

Yes

Step-by-step explanation:

Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.

When both machines work for 20 minutes

Machine A would produce = $\frac{20}{4} =5$ widget and

Machine B would produce = $\frac{20}{5} =4$ widgets

So we can say that Machine A would produce more widgets than Machine N at that time.

Answer is Yes

8 0

3 years ago

It's to hard and I can't figure it out

maria [59]

Answer:

The triangles are the same though, what do i do?

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help asappppp tyyy

True [87]

Given:

Compound shape

To find:

The area of the compound shape.

Solution:

The compound shape is splitted into two parallelograms.

<u>Bottom parallelogram:</u>

Base = 7.5 cm

Height = 5 cm

Area of the parallelogram = base × height

= 7.5 × 5

= 37.5 cm²

The area of the Bottom parallelogram 37.5 cm².

<u>Top parallelogram:</u>

Base = 7.5 cm

Height = 4.5 cm

Area of the parallelogram = base × height

= 7.5 × 4.5

= 33.75 cm²

The area of the top parallelogram 33.75 cm².

Compound shape = 37.5 + 33.75

= 71.25 cm²

The area of the compound shape is 71.25 cm².

7 0

3 years ago