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cupoosta [38]
4 years ago
11

Find the coordinates of the missing endpoint if m is the midpoint of AB.

Mathematics
1 answer:
Ne4ueva [31]4 years ago
7 0
E because its not on there
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What is the value of <br> 4x the power of 2 + 5x when x=1?
lana [24]

Answer:

the answer is 21

Step-by-step explanation:

4x to the power of 2 + 5x

so: 4*1 the power of 2 +5*1

4to power of 2 +5

and 4 to the power of 2 equals 16 (because 4*4=16) and +5

so 16+5=21

8 0
3 years ago
NEED HELP! This is for a test.
White raven [17]

Answer:

ML = 7.5

Step-by-step explanation:

The ratios are the same for both lines.

The one at the top has a 8:10 ratio and the one below has a 6:ML ratio

Convert to fractions and find the value of ML:

8/10 = 6/ML

8*ML= 6*10

ML= 60/8 = 7.5

3 0
3 years ago
On a number line, a number, b, is located the same distance from 0 as another number, a, but in the opposite direction
Karolina [17]

Answer:

b = -a

Step-by-step explanation:

We know that:

On a number line, the distance between 0 and b is the same distance that between 0 and a (but b and a are in opposite sides of zero).

And we know that, for example, when:

b = 2,  a = -2

Remember that the distance between two values is given by:

|n - m|

Then the distance between 0 and b is:

|0 - b|

and the distance between 0 and a is:

|0 - a|

we have:

|-b| = |-a|

|b| = |a|

But the numbers are in opposite sides of the zero, so one must be positive and the other negative, then we can conclude that:

b = -a

or

-b = a

(these are equivalent)

Then the correct option is the first option:

b = -a

6 0
3 years ago
What is 16 divided by X^2 equals 8 divided by X + 6?
zaharov [31]
Solve: \frac{16}{x^{2}} = \frac{8}{x + 6}

\frac{16}{x^{2}} = \frac{8}{x + 6}

\text{Cross multiply: } 16(x + 6) = 8x^{2}
\text{Simplify: } 2(x + 6) = x^{2}
\text{Expand: } 2x + 12 = x^{2}

\text{Solve for x: } x^{2} - 2x - 12 = 0

\text{Use the quadratic equation: } x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}
x = \frac{2 \pm \sqrt{4 + 48}}{2}
x = \frac{2 \pm \sqrt{52}}{2}
x = \frac{2 \pm \sqrt{13 \cdot 4}}{2}

x = \frac{2 \pm 2\sqrt{13}}{2}
\therefore x = 1 \pm \sqrt{13}
7 0
3 years ago
Can someone please help me?
oksano4ka [1.4K]
1) 12
2) 2y
3) 12+2y
4) 12+2y
8 0
3 years ago
Read 2 more answers
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