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4 years ago

Prove that.........

Mathematics

1 answer:

tresset_1 [31]4 years ago

8 0

Answer:

becauz the cos .1sj sin A the thing cos

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there Are 3 brothers, Daryl, Malik, and Terrance who’s ages add up to 26 years. Daryl is 3 times as old as Mail, and Terrance is

Scorpion4ik [409]

Answer:

Daryl = 9, Malik = 3, Terrance = 14

Step-by-step explanation:

We can use letters to represent each brother's name, so

D + M + T = 26

3M = D

D + 5 = T

then we can plug in the 3M in the third problem for D

3M + 5 = T

Then we can go back to the first problem and plug in 3M and (3M + 5)

3M + M + (3M + 5) = 26

4M + (3M + 5) = 26

7M = 21

M = 3

plug 3 in for M in the second equation:

3 x 3 = D

D=9

Then go back to the first equation:

9 + 3 + T = 26

12 + T = 26

T = 14

So T = 14

D = 9

and M = 3

4 0

3 years ago

Read 2 more answers

A secondhand clothing store finds that 1/6 of the donations they receive are not in good enough condition to be sold. Of those i

prohojiy [21]

Answer:

1/8

Step-by-step explanation:

3/4 x 1/6=1/8

8 0

3 years ago

The product of 8 and the difference between a number and 9 is 96. what is the number?

Tomtit [17]

The number is 21. First you should divide 96 by 8 to find the 'product' that it talks about. That number is 12. So the product of 8 and 12 is 96. But, then you have to find the difference between a number and nine that makes 12. Easy! Just add 9 and 12, and you get 21 as your answer!

3 0

3 years ago

16. From past experience, a company has found that in cartons of transistors, 92% contain no defective transistors, 3% contain o

Lynna [10]

Answer:

E(x)=0.15

V(x)=0.3075

S(x)=0.5545

Step-by-step explanation:

The mean of a discrete variable is calculated as:

$E(x)=x_1*p(x_1)+x_2*p(x_2)+...+x_n*p(n)$

where $x_1,x_2,...,x_n$ are the values that the variable can take and $p(x_1),p(x_2),...,p(x_n)$ are their respective probabilities.

So, if we call x the number of defective transistors in cartons, we can calculate the mean E(x) as:

$E(x)=(0*0.92)+(1*0.03)+(2*0.03)+(3*0.02)=0.15$

Because there are 0 defective transistor with a probability of 0.92, 1 defective transistor with a probability of 0.03, 2 defective transistors with a probability of 0.03 and 3 defective transistors with a probability of 0.01.

At the same way, the variance V(x) is calculated as:

$V(x)=E(x^2)-(E(x))^2$