Write the equation of the function of a parabola with vertex at (–1,–2) and a point (1,–6) that lies on the curve.
1 answer:
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You can solve this problem through factoring.
First, you have the equation,
Then, you can factor the numerator.
You can cancel out the x-6 in both the numerator and the denominator because they would equal to just 1.
You are left with
The function is removable noncontinuous at x=6 because if you plug in 6 in x-6, your denominator would be undefined.
Answer: Option a.
Step-by-step explanation:
Make the denominator equal to zero and solve for x:
Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:
Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2
The answer is the option a.