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lutik1710 [3]
2 years ago
12

Write the equation of the function of a parabola with vertex at (–1,–2) and a point (1,–6) that lies on the curve.

Mathematics
1 answer:
Olenka [21]2 years ago
4 0

Answer:

f(x) = -(x + 1)² - 2

Step-by-step explanation:

f(x) = a(x - h)² + k

-6 = a(1 - -1)² + -2

-6 = a(4) -2

-4 = 4a

a = -1

f(x) = -(x + 1)² - 2

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In the statement, “Weight is a function of height,” which variable is the input and which is the output?
3241004551 [841]

Answer:

A. Height is input, Weight is output

Step-by-step explanation:

We are given the statement,

"Weight is a function of height".

As we know,

<em>In a function of the form y=f(x), the input variable is 'x' and the output variable is 'y'.</em>

If we write the given statement in the form y=f(x), we get,

Weight=f(Height)

This means that the input variable is 'Height' and the output variable is 'Weight'.

Hence, option A is correct.

5 0
2 years ago
Jake has decided to invest in three business ventures. The total cost of investing in all three ventures is $15,000. The combine
Arte-miy333 [17]
X = first venture, y = second venture, z = third venture

x + y + z = 15,000
x + z = y + 7000
3x + 2y + 2z = 39,000
these are ur equations.....

x + y + z = 15,000
x - y + z = 7000
--------------------add
2x + 2z = 22,000

x + y + z = 15,000....multiply by -2
3x + 2y + 2z = 39,000
-------------------
-2x - 2y - 2z = - 30,000 (result of multiplying by -2)
3x + 2y + 2z = 39,000
------------------add
x = 9,000

2x + 2z = 22,000
2(9000) + 2z = 22000
18,000 + 2z = 22000
2z = 22000 - 18000
2z = 4000
z = 4000/2
z = 2,000

x + y + z = 15,000
9000 + y + 2000 = 15,000
11,000 + y = 15,000
y = 15,000 - 11,000
y = 4,000

first venture (x) = 9,000 <==
second venture (y) = 4,000 <==
third venture (z) = 2,000 <==
7 0
2 years ago
Read 2 more answers
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Dafna1 [17]
The answer is 22 I looked it up to make sure i was right
7 0
2 years ago
This is Grade 9 Mathematics so I kinda stuck here so, if somebody can help me Please sin30⁰+csc60⁰​
mamaluj [8]

\huge\mathrm{Answer࿐}

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To remove √3 from denominator, we multiply both numerator as well as denominator with √3

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____________________________

\mathrm{ \#TeeNForeveR}

6 0
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4 0
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