For anybody who has had this question 0 and 5 :(
1 answer:
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No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
or 
so
if w^2-9w+81 is perfect square, factored form is either
or 
aka 
or 
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
so
if w^2-9w+81 is perfect square, factored form is either
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is
Another possible answer is
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have
In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)