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svet-max [94.6K]
3 years ago
9

Subtract (5y3 + 6y + 3y4) from (4y4 - 8y3).

Mathematics
2 answers:
creativ13 [48]3 years ago
8 0

Answer:

a

Step-by-step explanation:

mash [69]3 years ago
4 0

Answer:

A) y ^4 −  13 y^ 3  −  6 y

Step-by-step explanation:

     4y^4 - 8y^3

-    5y^3 + 6y + 3y^4

----------------------------

flip the equations around

  -8y^3 + 4y^4

-   5y^3 + 6y + 3y^4

------------------------

-13y^3 - 6y + y^4

Rearrange to get:

y^4 - 13y^3 - 6y

<u>I hope this helps you out!!!</u>

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There are two functions that can be used to describe the percent of people 25 years and older who have completed at least high s
Korvikt [17]

Answer:

g(15)=93.8\%

see the explanation

Step-by-step explanation:

Let

x ----> the number of years since 2008,

g(x) ----> the percent of people 25 years and older who have completed at least high school

we know that

g(x)=0.008x^2+0.42x+87.5

so

For x=15 years since 2008

substitute

g(15)=0.008(15)^2+0.42(15)+87.5=93.8\%

That means

In the year 2023 (2008+15) the percent of people 25 and older completing at least high school will be 93.8%

5 0
3 years ago
What is the domain of the function
Nesterboy [21]

Answer:

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7 0
3 years ago
Irene tiene una colección de 50 dvd de películas de 90 minutos de duración cada una .Si el precio de cada uno era de 11€ , ¿cuan
Rainbow [258]

To solve this problem you must apply the proccedure shown below:

1. She has a total of 50 DVDs of 90 minutes each one of them. The cost of each DVD was 11€.

2. Therefore, to calculate the total cost of the collection, you must multiply the cost of each DVD by the total number of them:

total=(11)(50)=550€

3. To calculate the total minutes of the collection, you must multiply 90 minutes by the total number of DVDs:

(90min)(50)=4500min

Therefore, the answer is: 550€ and 4500 minutes.

3 0
3 years ago
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
If Z is the midpoint of RT , what are x, RZ AND RT?
Novosadov [1.4K]
Since z is the midpoint, rz and zt must be equal

4x - 15 = 25

4x = 40

X = 10
Plug the answer in and rz equals 40-15 which is 25.

25 + 25 = 50

Or if you really wanted, since you know 25 is half, just add them together right off the bat. (25 and 25, I mean)



5 0
3 years ago
Read 2 more answers
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