Look at the picture.
Corresponding Angles are equal.
Alternate Angles are equal.
Consecutive Angles add up to 180°.
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3a and 45 are Consecutive Angles. Therefore
3a + 45 = 180 |subtract 45 from both sides
3a = 135 |divide both sides by 3
<h3>a = 45.</h3>
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(2c - 1) and 45 are Corresponding Angles. Therefore
2c - 1 = 45 |add 1 to both sides
2c = 46 |divide both sides by 2
<h3>c = 23.</h3>
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3a and (12b + 3) are Alternate Angles. Therefore
3(45) = 12b + 3
135 = 12b + 3 |subtract 3 from both sides
132 = 12b |divide both sides by 12
<h3>b = 11.</h3>
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Answer:
q/2, p, q
Step-by-step explanation:
You know the area of a triangle is half the product of base and height. The two triangles of interest here have base length p and height q/2. You're being asked to fill in the missing base or height dimension.
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The answer is B im doing sum rn but its B ok
