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3 years ago

11

What numbers are divisible by 3

2 answers:

steposvetlana [31]3 years ago

7 0

Tbh idrk but uh thanks for the points

creativ13 [48]3 years ago

7 0

Answer:

An easy trick to find out: A number is divisible by 3 if the sum of its digits is divisible by 3. For example, 375, 3+7+5=15. 15 is divisible by 3, so 375 is too.

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T = L(8 + RS)<br> Solve for R

Eddi Din [679]

Answer:

Step-by-step explanation:

T=L(8+RS)

T=L8+LRS

T-L8=LRS

R=T-L8/LS

6 0

4 years ago

Goshia [24]

Answer:

x = 25

$m\angle \: MPQ = 125 \degree$

Step-by-step explanation:

$5x \degree = (3x + 50) \degree \\(corresponding \:\angle s) \\\\ 5x = 3x + 50 \\ \\ 5x - 3x = 50 \\ \\ 2x = 50 \\ \\ x = \frac{50}{2} \\ \\ x = 25 \\ \\ m\angle MPQ = (3x + 50) \degree \\ \\ m\angle MPQ = (3 \times 25 + 50) \degree \\ \\ m\angle \: MPQ = (75 + 50) \degree \\ \\ m\angle \: MPQ = 125 \degree \\ \\$

3 0

3 years ago

F(x)=13x-14<br> Find the domain of f(x)

Igoryamba

$D_f:x\in\mathbb{R}$

5 0

3 years ago

A supermarket offers a delivery service. If a customer pays $9 per month, each delivery costs just $2. Write an equation that sh

Rzqust [24]

The linear function that models the total cost for x deliveries is:

$y(x) = 2x + 9$

-------------------

A linear function has the following format:

$y = mx + b$

In which

m is the slope, that is, the rate of change.
b is the y-intercept, that is, the value of y when x = 0.

In this problem:

Fixed cost of $9 per month, $b = 9$ .
Cost of $2 for each delivery, thus $m = 2$ .

The function for the <u>total cost for x deliveries is:</u>

$y(x) = 2x + 9$

A similar problem is given at brainly.com/question/16270359

4 0

3 years ago

Joes electric made 19 customer calls last week and 25 this week. How many calls must be made next week in order to maintain an a

Mkey [24]

Answer:

At least 16 calls must be made.

Step-by-step explanation:

It is given that Joes electric made 19 customer calls last week and 25 this week.

Let x calls be made next week in a order to maintain an average of at least 20 calls per week for three week period.

$Average=\dfrac{\text{Sum of observations}}{\text{Number of observations}}$

$Average=\dfrac{19+25+x}{3}$

$Average=\dfrac{44+x}{3}$

Average at least 20.

$Average\geq 20$

$\dfrac{44+x}{3}\geq 20$

$44+x\geq 60$

$x\geq 60-44$

$x\geq 16$

Hence, at least 16 calls must be made.

7 0

3 years ago