$x^2+6x-27=0\\\\x^2-3x+9x-27=0\\\\x\big(x-3\big)+9\big(x-3\big)=0\\\\\big(x+9\big)\big(x-3\big)=0\\\\\\x+9=0\qquad\vee\qquad x-3=0\\\\\boxed{x=-9\qquad\vee\qquad x=3}$

8 0

4 years ago

If the slope of line L is -2/5, what is the slope of line m so that line l and line m are perpendicular?

ki77a [65]

Perpendicular lines have negative reciprocal slopes. So if the slope is -2/5...to find the negative reciprocal, " flip " the slope and change the sign.
So we flip -2/5 and we get 5/-2...and now we change the sign...and we get 5/2. So our perpendicular slope will be 5/2.

3 0

4 years ago

Use the zero property product to find the solutions to the equation x^2-9= 16

Luba_88 [7]

Subtract 16 to get
x^2 -25 = 0
Factor this as
(x -5)(x +5) = 0

The zero product property tells you the product will be zero when one of the factors is zero.

For x-5 = 0
x = 5

For x+5 = 0
x = -5

The appropriate choice is
3) x=-5 or x=5

4 0

3 years ago

F(x)= x^2<br><br> What is f(x) + f(x) + f(x)?

Alik [6]

Answer:

$3x^2$

Step-by-step explanation:

since $f(x)= x^2$ , We can substitue for $x^2 + x^2 + x^2$

7 0

3 years ago

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