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Lerok [7]
3 years ago
13

Please answer and simplify -5/8 + (-8/5)

Mathematics
2 answers:
kirza4 [7]3 years ago
7 0

\text{First, find the common denominator for the fractions}\\\\-\frac{5}{8}+(-\frac{8}{5})\\\\\text{We know that they both can multiple to 40, 8 times 5; 5 times 8}\\\\\text{The multiplying you're doing in the bottom, you will do the same for}\\\text{the top}\\\\\text{Your expression should look like this:}\\\\-\frac{25}{40}+(-\frac{64}{40})\\\\\text{Add across}\\\\\boxed{-\frac{89}{40}}\\\\\text{You can't simplify it any further, so that would be the simplest form}\\\text{in a improper fraction}

\text{In you need it as a mixed number, your answer would be:}\\\\\boxed{-2\frac{9}{40}}

alexandr402 [8]3 years ago
6 0

Answer:

-89/40 or simplified it is -2 9/40

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Calculate the answer to the correct number of significant digits. (91.01)(10.7)
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Answer:

974

Step-by-step explanation:

(91.01)*(10.7)

91.01*(10.7)

91.01*10.7

973.80700

974

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3 years ago
How much cm³ is it the cilinder?
pychu [463]

Answer:

one because it is cilinder

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2 years ago
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Enter the answer to the problem below, using the correct number of
Setler [38]

Answer:

<h2><em>55.112</em></h2>

Step-by-step explanation:

This is correct all you do is add them up like this:

30.27

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+22.952

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55.112

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3 years ago
Please help me out here, I’ve been reposting the same questions and have not seen people not answer mine. :( just please i will
anastassius [24]

Answer:

There are infinite solutions because they are the same equation

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2 years ago
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A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

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  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

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 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
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