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3 years ago

How to find the inverse of h(x) = 3/ -x - 2 List steps.

1 answer:

7 0

To find the inverse,

First, you would have to switch the domain and range. In other words, swap x and y:

h(x) = 3/ -x-2
y = 3/ -x-2
x = 3/ -y-2

Then, when you have this, simply solve for y:

x = 3/-y-2
x (-y-2) = 3/-y-2 (-y-2)
x(-y-2) /x= 3 /x
-y-2 = 3/x
-y = 3/x + 2
y = -3/x -2

So the inverse would be
h⁻¹(x)= -3/x -2

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A paint company mixes it's paint with water to create more paint per gallon. They currently have ten gallon jugs which contain 1

Karo-lina-s [1.5K]

<h3>Answer: 1.25 gallons</h3>

==================================

Explanation:

They currently have ten gallon jugs that contain 10% water, so this means 0.10*10 = 1 gallon of the jug is water and the other 10-1 = 9 gallons is paint. This is assuming the cans are just paint and water.

The ratio of paint to water is 90:10 which reduces to 9:1

Often it helps to reduce as much as possible, but it's actually more handy in this case to keep it at 90:10 so you can see the two parts add back up to 100%

--------------

Let x be the amount of water we add. This amount is in gallons.

We start off with 1 gallon of water and it bumps up to 1+x gallons of water.

The overall amount of 10 gallons also bumps up to 10+x gallons.

We want a ratio of 80:20 this time, so we want 20 parts water and 80 parts paint. In other words, we want 20/(20+80) = 20/100 = 20% water

Divide (1+x) over (10+x) to get (1+x)/(10+x). This represents the fraction of water. We want this fraction to be equal to 0.20, which is the 20% water amount. It is also equal to 20/100.

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(1+x)/(10+x) = 20/100

100(1+x) = 20(10+x) ... cross multiply

100+100x = 200+20x ... distribute

100x-20x = 200-100

80x = 100

x = 100/80 ... divide both sides by 80

x = 1.25

You need to add 1.25 gallons of water

--------------

If you add 1.25 gallons of water, then,

amount of water = 1+x = 1+1.25 = 2.25

amount of paint&water = 10+x = 10+1.25 = 11.25

So you'll have 2.25 gallons of water out of 11.25 gallons of water&paint mix

2.25/11.25 = 0.2 = 20% water

This confirms our answer.

--------------

Extra info:

1.25 gallons = 1 gallon + 1/4 gallon

1.25 gallons = 1 gallon + 1 quart

This is because 1 gallon = 4 quarts, so 1 quart = 1/4 gallon.

5 0

3 years ago

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago

Mr. Gonzales is replacing a cylindrical air-conditioning duct. He estimates the radius of the duct by folding a ruler to form tw

GalinKa [24]

Answer:

<em><u>5.6875 in</u></em>

Explanation:

At the point of tangency, the <em>tangent </em>to a circle and the <em>radius</em> form a right triangle (the radius is perpendicular to the tangent).

Here you are given the length of the tangent (6in), and the distance from the bisected vertex to the circle (2.75 in)

I tried to upload the drawing but the tool is not allowing it now.

In the figure:

The length of the tangent (6 in) is one leg of the triangle
The distance from vertex and the circle (2.75in) along with the radius forms the hypotenuse of the right triangle: 2.75 + r.
The other leg is the radius, r.

Then, you can use Pythagorean theorem:

(r)² + (6)² = (r +2.75)²

Solve:

r² + 36 = r² + 5.5r + 7.5625

5.5r = 36 - 7.5625

5.5r = 28.4375

r = 5.6875

The solution is in inches: r = 5.6875 inches ← answer

4 0

2 years ago

No link nor file pease help im crying about these questions

lora16 [44]

Answer:

Step-by-step explanation:

10.5*2/3= 3.5*2=7

5 0

2 years ago

Read 2 more answers

Veronica has 7 yards of ribbon. Each bow requires 3/4 of a yard ribbon. How many bows will she be able to make with the ribbon s

Sonbull [250]

Answer && Step-by-step explanation:

7 yards == 4/4

by simple arithmetic remove 3/4 from 7 until you can no longer obtain 3/4 from it

7 => 6*1/4

6*1/4=>5*2/4

5*2/4=>4*3/4

4*3/4=>4

4=> 3*1/4

3*1/4=>2*2/4

2*2/4=>1*3/4

1*3/4=>1

1=>1/4

1/4 remains and 9 bows were made

8 0

3 years ago