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Serga [27]
3 years ago
7

Are the ratios 5:4 and 9:6 equivalent?

Mathematics
2 answers:
Jlenok [28]3 years ago
7 0
No, these ratios are not equivalent.
Archy [21]3 years ago
5 0
Nope. 5:4 equals 15:12, when 9:6 equals 18:12
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You go to the electronics store to buy 3 CDs. Each CD's original cost is $9.99. You have a coupon for 10% off and the sales tax
Afina-wow [57]

Answer:

$28.77

Step-by-step explanation:

What you do is the coupon for 10% off first which equaled 2.997, but you have to round to $3.00.

You minus 3*9.99 which equals $29.97 and $3.00 to get $26.97.

You then times $29.97 by 6% to get 1.80.

You then add it to $26.97.

You get $28.77.

6 0
3 years ago
Find the sum of the measures of the interior angles of the indicated convex polygons.
likoan [24]

Answer:

1. 17 - gon

sum of the of measures of interior angles = 180(n-2).....(formula)

here n = 17

therefore, 180(17-2)

= 180(15)

= 2700 degrees

2] 24 - gon

sum of the of measures of interior angles = 180(n-2).....(formula)

here n = 24

therefore, 180(24-2)

= 180(22)

= 3960 degrees.

7 0
3 years ago
Worth LOTS OF POINTS PLZ!<br><br> Is -1/2n+ 1 1/2n+3-n equivalent to 3 ? Explain
tino4ka555 [31]
The answer is 3. -1/2 n + 1 1/2 n add the coefficients to get 1n or just n. then n-n is 0 what is left is 3.
5 0
3 years ago
A 250-gal tank is initially filled with brine (salt-water mixture) containing 100 lb of salt. Brine containing 3 lb of salt per
gulaghasi [49]

Answer:

x(t) = 581.66 lb

Step-by-step explanation:

From the given information:

Consider the salt quantity in the tank at time t be x(t) lb.

∴ the rate of change of salt content in the tank is \dfrac{dx}{dt}= Rate \ of \  \ inflow - rate \ of \  \ outflow

where:

the rate of inflow = salt conc. × flow rate = 3 lb/gallon × 7 gallons

=21 lb/s

rate of outflow = salt conc. in the tank  × flow rate

= x/250 ×  9

= 9x/250  lb/s

∴

\dfrac{dx}{dt} = 21 - \dfrac{9x}{250}

\dfrac{dx}{dt} + \dfrac{9x}{250}= 21

This is a 1st order linear differentiation,

The integrating factor if e^{^{ \int \dfrac{9}{250}\ dt}} = e^{^{ \dfrac{9t}{250} }}

∴

e^{^{ \dfrac{9t }{250}}} \ \ x(t) = \int 21 e^{\dfrac{9t}{250}} \ dt + C

e^{^{ \dfrac{9t }{250}}} \ \ x(t) =  21 \times \dfrac{250}{9}e^{\dfrac{9t}{250}} + C

x(t) = \dfrac{1750}{3}+Ce^{^{\dfrac{-9t}{250}}}     at  t = (0) and x(0) = 100 lb

Hence;

100 = \dfrac{1750}{3}+C

C = \dfrac{1750}{3} -100

C = - \dfrac{1450}{3}

∴x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9t}{250}}}

after time t = 1 minute i.e 60 s

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9 \times 60}{250}}}

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-540}{250}}}

x(t) = 581.66 lb

5 0
4 years ago
Help me get the solution pls..​
lina2011 [118]

Answer:

R+56°+29°= 180°

R = 95°

Step-by-step explanation:

Hope it helps you!

4 0
3 years ago
Read 2 more answers
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