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3 years ago

Help me with this please

Mathematics

2 answers:

Vesnalui [34]3 years ago

6 0

I think it's -6r/s but I'm not sure

Maurinko [17]3 years ago

3 0

The answer is $\frac{-6r}{s}$

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The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. Find the width and length.

Brums [2.3K]

Let the width = x
=>length = 2x-1

91= x(2x-1)=2x^2-x
2x^2-x-91=0
=(2x+13)(x-7)
=> x=-13/2=> no
=>x= 7 cm

7 0

3 years ago

A recipe calls for 3 times as many chocolate chips as butterscotch chips. If there are 25 oz of chocolate chips, how many oz do

Bingel [31]

The amount, in oz of butterscotch chips needed by proportional reasoning is; 75oz.

<h3>What is the amount of butterscotch chips needed by proportional reasoning?</h3>

It follows from the task content that the the amount of butterscotch chips needed can be determined by means of the proportion premise declared in which case;

The recipe requires 3 times as many chocolate chips as butterscotch chips.

Hence, when 25oz of chocolate chips is used, the amount of butterscotch needed is 3 times 25 and hence, = 3 × 25 = 75oz.

Read more on proportion;

brainly.com/question/1496357

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4 0

2 years ago

Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.

dmitriy555 [2]

see the attached figure to better understand the problem

we have that

$cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units$

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

$cos (A)=(AC/AB)\\AC=AB*cos(A)$

substitute the values in the formula

$AC=12*(1/5)\\ AC=2.4\ units$

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

$AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}$

substitute the values

$BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units$

Step 3

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

$BD^{2} =DC^{2}+BC^{2}$

substitute the values

$BD^{2} =2^{2}+11.76^{2}$

$BD=11.93\ units$

therefore

<u>the answer is</u>

the length of BD is 11.93 units

8 0

3 years ago

Read 2 more answers

A professor gives her 100 students an exam; scores are normally distributed. The section has an average exam score of 80 with a

frozen [14]

Answer:

6.18% of the class has an exam score of A- or higher.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 80, \sigma = 6.5$