The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer:
X Y
1 5
4/5 4
2/5 2
Step-by-step explanation:
y=5x
We we know y we need to solve for x
X Y
5
4
2
Let y =5
5 = 5x
Divide by 5
5/5 =5x/5
1=x
Let y =4
4 = 5x
Divide by 5
4/5 =5x/5
4/5=x
Let y =2
2 = 5x
Divide by 5
2/5 =5x/5
2/5=x
X Y
1 5
4/5 4
2/5 2
<u>Answer:</u>
<h3>(
) x (
) </h3>
<u>Step-by-step explanation:</u>
To find the area of a rectangle, we have to multiply the length with the width.
In the question, the given length is 'x' and the width given is 'x +7'
So, the area would be
( ) x ( )
The area = 
So, the equation to find the area of such a rectangle would be:-
( ) x ( )
(x, y ) → (- 1, 3 )
The solution to the system of equations is the point of intersection of the 2 lines
From the graph, that is (x, y ) → ( - 1, 3 )
We can confirm by solving algebraically
Since both equations express y in terms of x we can equate the right sides
- x + 2 = - 6x - 3 ( add 6x to both sides )
5x + 2 = - 3 ( subtract 2 from both sides )
5x = - 5 ( divide both sides by 5 )
x = - 1
substitute x = - 1 into either of the 2 equations for y-coordinate
y = - x + 2 = 1 + 2 = 3
solution is (x, y ) → (- 1, 3 )
