Question

Use the formula V=6s2 to find the surface area of a cube with the sides of length a = 1/3 cm

Answer 1

Answer:

$V = \frac{2}{3} cm^2$

Step-by-step explanation:

Given

$V = 6s^2$

Required

Find the surface area when the length is $\frac{1}{3}\ cm$

To do this, we simply substitute $\frac{1}{3}\ cm$ for s in the given formula

$V = 6s^2$ becomes

$V = 6 * \frac{1}{3}^2$

$V = 6 * \frac{1}{3} * \frac{1}{3}$

Combine Fractions

$V = \frac{6 * 1 * 1}{3 * 3}$

$V = \frac{6}{9}$

Simplify Fraction

$V = \frac{2}{3} cm^2$