Part A : 30 - x - x - x - x - x - x = 0
^ since 30 divided by 5 is 6, that answer is the same as doing 5 + 5 + 5 + 5 + 5 + 5
- pls comment & correct me if i did smth wrong :’)
Answer:
y = 0.15x+77 is the equation linear connecting total cost y and miles driven x
Step-by-step explanation:
Given that the leasing company charged a flat rental fee for the week, plus a charge for each mile driven.
Let flat rental fee be c and cost per mile driven = m and miles driven = x
Total cost =y
Then y = mx+C is the linear equation.
to find m and c, we use the fact that y =110.30 when x = 222
i.e. 110.30 = c+222x
and similarly 99.05 = c+147x
Subtract to eliminate c
11.25 = 75 x
0.15 =x
Substitute in I equation
110.30 = c+222(0.15)
c = 77
Hence y = 0.15x+77 is the equation linear connecting total cost y and miles driven x
H=-t^2+95
The y intercept here is 95, and it represented from where the boy threw the ball.
If he threw it from 95 ft above the ground, the best answer for where he is is on a bridge.
His backyard is at 0 ft (sea level). An underground cave is below sea level. A ladder is probably not 95 ft.
Final answer: D
Answer:
y = 1/e
y = 0.37
Step-by-step explanation:
y = (ln x)/x; (e, 1/e)
Step 1
Find the point of tangency.
It's given as (e,1/e) or (2.72,0.37)
Step 2
Find the first derivative, and evaluate it at x=e
Using product rule.
d(uv) = udv + vdu
Where u = lnx and v = 1/x
du = 1/x , dv = -1/x^2
f'(x) = -lnx/x^2 +1/x^2
f'(x) = (1-lnx)/x^2
At x = e
f'(e) = (1-lne)/e^2
f'(e) = 0
The slope of the tangent line at this point is m= 0
Step 3
Find the equation of the tangent line at (e,1/e) with a slope of m=0
y−y1 = m(x - x1)
y-(1/e) = 0(x-1)
y = 1/e
y = 0.37
