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3 years ago

Simplify the expression (t^-2)^6

Mathematics

1 answer:

Rainbow [258]3 years ago

5 0

Answer:

t^-12

Step-by-step explanation:

you multiply the -2 and 6.

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If the hypotenuse of a right triangle measures 15 cm and one of the legs measures 12 cm, what is the length of the other leg?

Mama L [17]

Step-by-step explanation:

12 to the 2nd power=144

15 to the 2nd power =225

225-144=81

square root of 81 is 9

5 0

3 years ago

PLEASE ANSWER ASAP TODAY WILL GIVE BRAINLIEST TO FIRST RIGHT ANSWER.

Lisa [10]

Answer:

y-7=3(x-9)

Step-by-step explanation:

It appears they want your answer in point-slope form, which is identified by the equation y-y1=m(x-x1)

Step 1: Find the slope (m)

m=(y2-y1)/(x2-x1)

m=(-8-7)/(4-9)

m=(-15)/(-5)

m=3

The slope is m=3

Step 2: Plug in m, y1, and x1

y-y1=m(x-x1)

y-7=3(x-9)

Therefore our final equation is y-7=3(x-9)

7 0

3 years ago

A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment i

Tasya [4]

Answer:

(3,7) for the first line, and (12,0) for the second one.

Step-by-step explanation:

Hi Isabella,

1) The Midpoint of a line, when it comes to Analytical Geometry, is calculated as Mean of two points it follows:

$x_{m}=\frac{x_{1} +x_{2} } {2}, y_{m} =\frac{y_{1}+ y_{2} }{2}$

2) Each segment has two endpoints, and their midpoints, namely:

a) (1,-9) and its midpoint (2,-1)

b) (-2,18) and its midpoint (5,9)

3) Calculating. You need to be careful to not sum the wrong coordinates.

So be attentive!

The first line a

$2=\frac{1+x_{2} }{2}\\ 4=1+x_{2}\\ 4-1=-1+1+x_{2} \\ x_{2}=3\\-1=\frac{y_{2}-9}{2}\\-2=y_{2}-9\\+2-2=y_{2}-9+2\\ y_{2}=-7$

So (3,7) is the other endpoint whose segment starts at (1,-9)

The second line b endpoint at (-2,18) and its midpoint (5,9)

$5=\frac{-2+x_{2} }{2} \\ 10=-2+x_{2} \\ +2+10=+2-2+x_{2}\\ x_{2}=12 \\ \\ 9=\frac{18+y_{2} }{2} \\ 18=18+y_{2} \\ -18+18=-18+18+y_{2}\\ y_{2} =0$

So (12,0) it is the other endpoint.

Take a look at the graph below:

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3 years ago

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VladimirAG [237]

Please find the attached image

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3 years ago

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aliya0001 [1]

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3 years ago