<h3>
Answer: ds/dt = 11</h3>
================================================
Work Shown:
Before we can use derivatives, we need to find the value of s when (x,y) = (15,20)
s^2 = x^2+y^2
s^2 = 15^2+20^2
s^2 = 225+400
s^2 = 625
s = sqrt(625)
s = 25
-----------
Now we can apply the derivative to both sides to get the following. Don't forget to use the chain rule.
s^2 = x^2 + y^2
d/dt[s^2] = d/dt[x^2 + y^2]
d/dt[s^2] = d/dt[x^2] + d/dt[y^2]
2s*ds/dt = 2x*dx/dt + 2y*dy/dt
2(25)*ds/dt = 2(15)*5 + 2(20)*(10)
50*ds/dt = 150 + 400
50*ds/dt = 550
ds/dt = 550/50
ds/dt = 11
-----------
Side note: The information t = 40 is never used. It's just extra info.
Answer:
26042.
Step-by-step explanation:
What's the first term of this geometric series?
2.
What's the common ratio of this geometric series?
Divide one of the terms with the previous term. For example, divide the second term -10 with the first term 2.
.
What's the sum of this series to the seventh term?
The sum of the first n terms of a geometric series is:
,
where
is the first term of the series,
is the common ratio of the series, and
is the number of terms in this series.
.
This is a pathagorean triple is this triangle is a right triangle
