Given:
Capacity of jet plane = 200,000 liters of fuel
Fuel used during flight = 130,000 liters
To find:
The percentage of the fuel capacity it uses on this flight.
Solution:
According to the question, we need to find 130,000 is what percent of 200,000.
Therefore, the jet plane uses 65 percent of fuel capacity during flight.
Im not in this math section yet but i think that you can look it up as a worksheet and find the answer on google.
Answer:
K(x, y) —> K’(-x, y - 7)
Step-by-step explanation:
You would need to isolate the "X" variable because it is common in all 3 equations.
Answer:
9 1/3, 12 1/2, 14 3/4
Step-by-step explanation:
I assume the formula you’re working with is A=b*h since nothing says otherwise...
((Patio 1))
So you have your area (147) and your base (15 3/4), now you need to plug them in, which should look like this:
147= 15 3/4*h
You need to isolate your h in order to get the missing number, so you should divide both sides by 15 3/4 OR 63/4 ((15*3—>60+3=63))
Dividing by a fraction is the equivalent of multiplying by its reciprocal... so
147 * 4/63 = 588/63 which can be simplified to 84/9 once both the numerator and denominator are divided by 7
In mixed number for it is 9 3/9 which simplified becomes 9 1/3
You solve the other similarly
