How can (1/2)x-5=(1/3)x+6 be set up as a system of equations?

Mathematics

1 answer:

leonid [27]3 years ago

8 0

Answer:

2y-x=-10
3y-x=18

Step-by-step explanation:

Set each side of the equation equal to y, then rearrange to standard form.

(1/2)x -5 = y . . . left side of the equal sign

x -10 = 2y . . . . multiply by 2

-10 = 2y -x . . . . subtract x

(1/3)x +6 = y . . . right side of the equal sign

x +18 = 3y . . . . . multiply by 3

18 = 3y -x . . . . . subtract x

The corresponding system of equations is ...

2y -x = -10
3y -x = 18

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