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Luba_88 [7]
3 years ago
6

How can (1/2)x-5=(1/3)x+6 be set up as a system of equations?

Mathematics
1 answer:
leonid [27]3 years ago
8 0

Answer:

 C)

  • 2y-x=-10
  • 3y-x=18

Step-by-step explanation:

Set each side of the equation equal to y, then rearrange to standard form.

  (1/2)x -5 = y . . . left side of the equal sign

  x -10 = 2y . . . . multiply by 2

  -10 = 2y -x . . . . subtract x

__

  (1/3)x +6 = y . . . right side of the equal sign

  x +18 = 3y . . . . . multiply by 3

  18 = 3y -x . . . . . subtract x

The corresponding system of equations is ...

  • 2y -x = -10
  • 3y -x = 18
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Variance and standard deviation
kirza4 [7]

Answer: 8.3

Step-by-step explanation:

To find the variance, you want to find the mean of the data.

\frac{3+3+8+1+9+6}{6} =5

Now that we have the mean, we find the difference between each data point and the mean.

3-5=-2

3-5=-2

8-5=3

1-5=-4

9-5=4

6-5=1

With the difference, you square each and find the average.

(-2)²=4

(-2)²=4

3²=9

(-4)²=16

4²=16

1²=1

\frac{4+4+9+16+16+1}{6} =\frac{25}{3}

The variance is 8.3.

3 0
3 years ago
From 1st principle find the derivative of log (ax+b)
OLga [1]

Answer:

Step-by-step explanation:

The parent function here is y = log x, where 10 is the base.

The derivative of y = log x is dy/dx = (ln x) / ln 10.

The derivative of y = log (ax+b) is found in that manner, but additional steps are necessary:  differentiate the argument ax + b:

The derivative with respect to 10 of log (ax + b) is:

dy/dx = [ 1 / (ax + b) ] / [ ln 10 ] *a, where a is the derivative of (ax + b).

Alternatively, we could express the answer as

dy/dx = [ a / (ax + b) ] / [ ln 10 ]

5 0
3 years ago
I need help ASAP for my homework
bogdanovich [222]

Answer:

slope of line ax + by = c is -a/b

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3 0
3 years ago
Read 2 more answers
FUNCTION OR NOT /// ALGEBRA I
guapka [62]

Answer:

First figure: The graph is not a function

Second figure:

Statement 1: It is false

Statement 2: It is false

Statement 3: It is right

Step-by-step explanation:

First graph is not a function.

The domain of it is ⇒ 0 ≤ x < 3 , 3 < x ≤ 6 , 6 ≤ x < 9

From the domain ⇒ x = 6 has two corresponding values of y⇒ 3 and 4

∴ It is not a function because every x must have one and only one

  corresponding value of y

Second figure

{(3 , 6) , (4 , 6) , (5 , 7) , (6 , 8) , (7 , 10) , (8 , 10)}

<u>Statement 1</u>: It is false because we use x-value to check function or not.

The relation is a function because every x-value has one corresponding

y-value

<u>Statement 2</u>: It is false because 3 ≤ x ≤ 8 means we will use for x all real numbers from 3 to 8 not only the integers 3 , 4 , 5 , 6, ,7 , 8

The domain of this function is { 3 , 4 , 5 , 6 , 7 , 8 }

<u>Statement 3</u>: It is right because the range is the y-value and all the y-value in the function are 6 , 7 , 8 , 10

5 0
3 years ago
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SVETLANKA909090 [29]

Answer:

D. -9

Step-by-step explanation:

5f - 6f = 9 \\  - f = 9 \\ f =  - 9

7 0
3 years ago
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