2 years ago

Please help!!! Given the equation: x^2+6x+8=0

Mathematics

1 answer:

Tpy6a [65]2 years ago

7 0

Answer:

$(x+3)^2=1$

Step-by-step explanation:

Complete the square:

$x^2+6x+8=0$

$x^2+6x+8+1=0+1$

$x^2+6x+9=1$

$(x+3)^2=1$

Therefore, the equation rewritten in $(x-h)^2=k$ form is $(x+3)^2=1$

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