Question

Please help!!! Given the equation: x^2+6x+8=0

Answer 1

Answer:

$(x+3)^2=1$

Step-by-step explanation:

Complete the square:

$x^2+6x+8=0$

$x^2+6x+8+1=0+1$

$x^2+6x+9=1$

$(x+3)^2=1$

Therefore, the equation rewritten in $(x-h)^2=k$ form is $(x+3)^2=1$