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ololo11 [35]
3 years ago
8

Which equation is perpendicular to 3x - y = 9 and goes through the point (6,6)

Mathematics
1 answer:
Lelechka [254]3 years ago
6 0

Answer:

y = - \frac{1}{3} x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 3x - y = 9 into this form by subtracting 3x from both sides

- y = - 3x + 9 ( divide all terms by - 1 )

y = 3x - 9 ← in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, thus

y = - \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, 6) into the partial equation

6 = - 2 + c ⇒ c = 6 + 2 = 8

y = - \frac{1}{3} x + 8 ← equation of perpendicular line

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Answer:

y =  \frac{1}{8} x - 2  \frac{1}{4}

Step-by-step explanation:

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the slope and c is the y-intercept

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The product of the slopes of perpendicular lines is -1. Let the slope of line q be m.

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m= -1 ÷(-8)

m= ⅛

Substitute m= ⅛ into the equation:

y= ⅛x +c

To find the value of c, substitute a pair of coordinates that the line passes through into the equation.

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c =  - 2 -  \frac{1}{4}

c =  - 2 \frac{1}{4}

Thus, the equation of line q is y =  \frac{1}{8} x - 2 \frac{1}{4}.

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