Not sure but I think
a) 4/6 which is 66.67%
b) 2/6 which is 33.33%
c) 4/6 which is 66.67%
i haven’t even finished high school so please don’t blame me if im wrong I do think that is the answer
a. Let
be a random variable representing the weight of a ball bearing selected at random. We're told that
, so

where
. This probability is approximately

b. Let
be a random variable representing the weight of the
-th ball that is selected, and let
be the mean of these 4 weights,

The sum of normally distributed random variables is a random variable that also follows a normal distribution,

so that

Then

c. Same as (b).
Y = x + 6
y has to be greater than or equal to 6
x has to be greater than or equal to 0
I think its he didnt eliminate the same variables
Answer:
Is that you, Mommy?
Step-by-step explanation:
:)