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hichkok12 [17]
3 years ago
5

Use long division method to calculate 102 024 ÷ 156​

Mathematics
1 answer:
IgorC [24]3 years ago
3 0
The answer is 654
I have done the working in a paper
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for a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height,
kolbaska11 [484]

Problem

For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground

Solution

We know that the x coordinate of a quadratic function is given by:

Vx= -b/2a

And the y coordinate correspond to the maximum value of y.

Then the best options are C and D but the best option is:

D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a

The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.​

7 0
1 year ago
. The following is a recipe for Gazpacho, a cold vegetable soup. Write how much of each item in the
Andreyy89

Answer: 9 lb of fresh tomatoes

6 c peeled chopped cucumbers

3 c chopped red bell peppers

3 c chopped red onions

6 small jalapenos

6 garlic cloves

1 1/2 olive oil

6 limes, juiced

12 tsp balsamic vinegar

12 tsp Worcestershire sauce

3 tsp cumin

6 tsp salt

1 1/2 tsp black pepper

12 tsp basil

I really hope this helps.

Step-by-step explanation:

3 0
3 years ago
HELP!! 50 POINTS!!!
aalyn [17]

Step-by-step explanation:

We have been given a table, which represents the projected value of two different houses for three years.


Part A:

\text{Increase in value of house 1 after one year}=294,580-286,000

\text{Increase in value of house 1 after one year}=8580

\text{Increase in value of house 1 after two years}=303,417.40-294,580

\text{Increase in value of house 1 after two years}=8837.4

We can see from our given table that the value of house 1 is not increasing at a constant rate, while a linear function has a constant rate of change, therefore, an exponential function can be used to describe the value of the house 1 after a fixed number of years.

\text{Increase in value of house 2 after one year}=295,000-286,000

\text{Increase in value of house 2 after one year}=9,000

\text{Increase in value of house 2 after two years}=304,000-295,000

\text{Increase in value of house 2 after two years}=9,000

We can see from our given table that the value of house 2 is increasing at a constant rat that is $9,000 per year. Since a linear function has a constant rate of change, therefore, a linear function can be used to describe the value of the house 2 after a fixed number of years.

Part B:

Let x be the number of years after Dominique bought the house 1.

Since value of house 1 is increasing exponentially, so let us find increase percent of value of house 1.

\text{Increase }\%=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100

\text{Increase }\%=\frac{294,580-286,000}{286,000}\times 100

\text{Increase }\%=\frac{8580}{286,000}\times 100

\text{Increase }\%=0.03\times 100

\text{Increase }\%=3

\text{Increase }\%=\frac{303,417.40-294,580}{294,580}\times 100

\text{Increase }\%=\frac{8837.4}{294,580}\times 100

\text{Increase }\%=0.03\times 100

\text{Increase }\%=3

Therefore, the growth rate of house 1's value is 3%.

Since we know that an exponential function is in form: y=a*b^x, where,

a = Initial value,

b = For growth b is in form (1+r), where, r is rate in decimal form.

3\%=\frac{3}{100}=0.03

Upon substituting our values in exponential function form we will get,

f(x)=286,000(1+0.03)^x, where, f(x) represents the value of the house 1, in dollars, after x years.

Therefore, the function f(x)=286,000(1.03)^x represents the value of house 1 after x years.

Let x be the number of years after Dominique bought the house 2.

We can see that when Dominique bought house 2 it has a value of $286,000. This means that at x equals 0 value of house will be $286,000 and it will be our y-intercept.

Since value of house 2 is increasing 9000 per year, therefore, slope of our line be 9000.

Upon substituting these values in slope-intercept form of equation (y=mx+b) we will get,

f(x)=9000x+286,000, where, f(x) represents the value of the house 2, in dollars, after x years.

Therefore, the function f(x)=9000x+286,000 represents the value of house 2 after x years.

Part C:

Since values in exponential function increases faster than linear function, so the value of house 1 will be greater than value of house 2.

Let us find the value of house 1 and house 2 by substituting x=25 in our both functions.

f(25)=286,000(1.03)^{25}

f(25)=286,000*2.0937779296542148

f(25)=598820.48788

We can see that value of house 1 after 25 years will be approx $598,820.48.

f(25)=9000*25+286,000

f(25)=225,000+286,000

f(25)=511,000

We can see that value of house 2 after 25 years will be approx $511,000.

Since $511,000 is less than $598820.48, therefore, value of house 1 is greater than value of house 2.

6 0
3 years ago
Read 2 more answers
A mean equal to 5 cm. A simple random sample of wrist breadths of 40 women has a mean of 5.07
neonofarm [45]

Answer:

The value of the test statistic is z = 1.34

Step-by-step explanation:

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

Test if the mean is equal to 5:

This means that the null hypothesis is \mu = 5

A simple random sample of wrist breadths of 40 women has a mean of 5.07 cm. The population standard deviation is 0.33 cm.

This means that n = 40, X = 5.07, \sigma = 0.33

Find the value of the test statistic?

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{5.07 - 5}{\frac{0.33}{\sqrt{40}}}

z = 1.34

The value of the test statistic is z = 1.34

5 0
3 years ago
We want to use this information to determine if there is an effect of friendship. In other words, is the mean price when buying
saw5 [17]

Answer:

H0 : mu1 = mu2

Ha : mu1 ≠ mu2

Which means

Null hypothesis H0; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is the same/equal

Alternative hypothesis Ha; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is different (not equal)

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean(i.e it tries to prove that the old theory is true). While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

Therefore, for the case above;

H0 : mu1 = mu2

Ha : mu1 ≠ mu2

Which means

Null hypothesis H0; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is the same/equal

Alternative hypothesis Ha; the true mean price when buying from a friend mu1 and the true mean price when buying from a stranger mu2 is different (not equal)

5 0
3 years ago
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