2 years ago

SV is a midsegment of △RTU. If TU=y+38 and SV=y–9, what is the value of y?

Mathematics

1 answer:

pav-90 [236]2 years ago

8 0

Answer:

y = 56

Step-by-step explanation:

the midsegment SV is half the length of the side TU , that is

y - 9 = $\frac{1}{2}$ (y + 38) ← multiply both sides by 2 to clear the fraction

2y - 18 = y + 38 ( subtract y from both sides )

y - 18 = 38 ( add 18 to both sides )

y = 56

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