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erastovalidia [21]
2 years ago
11

SV is a midsegment of △RTU. If TU=y+38 and SV=y–9, what is the value of y?

Mathematics
1 answer:
pav-90 [236]2 years ago
8 0

Answer:

y = 56

Step-by-step explanation:

the midsegment SV is half the length of the side TU , that is

y - 9 = \frac{1}{2} (y + 38) ← multiply both sides by 2 to clear the fraction

2y - 18 = y + 38 ( subtract y from both sides )

y - 18 = 38 ( add 18 to both sides )

y = 56

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Answer:

a. -⅓

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Step-by-step explanation:

a. Gradient of line AB:

A(1, 3), B(7, 1)

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Gradient (m) = -⅓

b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.

Thus, the negative reciprocal of -⅓ = 3

Gradient of the line perpendicular to line AB = 3

c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:

We can write the equation using the point-slope form equation, y - b = m(x - a), where,

(a, b) represents a point on the line, and,

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We know that the gradient/slope (m) = 3

Also, a point, (a, b) = (4, 2).

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y - 2 = 3(x - 4)

y - 2 = 3x - 12

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5 0
2 years ago
6x + 11 = 21<br> Help I’m on a quiz and this question is so confusing
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Answer:

Step by Step Solution

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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Step by step solution :

STEP

1

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STEP

2

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Equations which are never true:

2.1      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

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One solution was found :

x = 5/3 = 1.667

3 0
3 years ago
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