-- Look at the places where the line crosses the 'x' axis and the 'y' axis.
   Between those two points, it goes forward 2 units, but only rises 1 unit.
   So the slope of the line is 1/2 .

-- Look again at the point where the line crosses the y-axis.
   At that point, y=1 .
   That's the "y-intercept".

Now you have the slope and y-intercept of the line.

The equation of ANY straight line is

   y = (slope)x + (y-intercept) .

You know what they both are, so you can easily write

   y = 1/2 x + 1 .

Is that one of the choices ?
Yes it is.
Good enough for me.
That must be the correct one.

With no "blah blah blah" required.

3 0

4 years ago

Read 2 more answers

For circle H, JN = x, NK = 2, LN = 3, and NM = 6. Solve for x. circle H with chords JK and LM intersecting at N inside the circl

vredina [299]

Answer:

x=9

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

$JN*NK=LN*NM$ ----> by intersecting chords theorem