Consider a binomial experiment with n trials and r successes. To construct a test for a proportion p, what value do we use for t
1 answer:
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Answer:
A bus can carry 22 students and a van can carry 11 students.
Step-by-step explanation:
Let the number of students bus can carry be 'b'.
Let the number of students van can carry be 'v'.
Given:
One High school:
Number of bus = 6
Number of vans = 5
Number of students = 187
So we can say that;
Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.
framing in equation form we get;
⇒ Equation 1
Also Given:
One High school:
Number of bus = 7
Number of vans = 2
Number of students = 176
So we can say that;
Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.
framing in equation form we get;
⇒ Equation 2
Now multiplying equation 2 by 5 we get;
⇒ Equation 3
Now multiplying Equation 1 by 2 we get;
⇒ Equation 4
Subtracting equation 4 from equation 3 we get;
Substituting value of b in equation 2 we get;
Hence A bus can carry 22 students and a van can carry 11 students.
Answer: 5x = 12 + 3
5x = 15 (divide both sides by 5 to get x)
Step-by-step explanation: