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Assoli18 [71]
2 years ago
13

What is the answer 3r =30

Mathematics
2 answers:
zhuklara [117]2 years ago
7 0

Answer:

r=10

Step-by-step explanation:

RUDIKE [14]2 years ago
5 0

Answer:

<h3>r = 10</h3>

Step-by-step explanation:

3r = 30 \\  \frac{3r}{3}  =  \frac{30}{3}  \\ r = 10 \\

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The mean number of automobiles entering a mountain tunnel per two-minute period is one. An excessive number of cars entering the
viva [34]

Answer:

A Poisson model seems reasonable for this problem, since we have the mean during the time interval.

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x)=\frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The mean number of automobiles entering a mountain tunnel per two-minute period is one.

This means that \mu = 1.

For a Poisson model to be reasonable, we only need the mean during the time interval. So yes, a Poisson model seems reasonable for this problem.

Find the probability that the number of autos entering the tunnel during a two-minute period exceeds three.

We want to find P(X>3)

Either this number is less or equal to 3, or it exceeds 3. The sum of the probabilities is decimal 1. So:

P(X \leq 3) + P(X > 3) = 1

P(X > 3) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-1}*1^{0}}{(0)!} = 0.3679

P(X = 1) = \frac{e^{-1}*1^{1}}{(1)!} = 0.3679

P(X = 2) = \frac{e^{-1}*1^{2}}{(2)!} = 0.1839

P(X = 3) = \frac{e^{-1}*1^{3}}{(3)!} = 0.0613

So

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3679 + 0.3679 + 0.1839 + 0.0613 = 0.981

Finally

P(X > 3) = 1 - P(X \leq 3) = 1 - 0.981 = 0.019

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

8 0
4 years ago
Angle DEF is an inscribed angle on a circle, and m∠DEF = 64°. What is the measure of arc DF?
Svetach [21]

Answer:

128°

Step-by-step explanation:

<u>The measure of an inscribed angle is half the measure of the intercepted arc.</u> That means that the intercepted arc is two times the inscribed angle.

Measure of the inscribed angle DEF is 64°, that means that the measure of the intercepted arc DF is 2×64°, which is 128°.

m\overset{\huge\frown}{DF} = 2 \times m\angle DE F = 2 \times 64^\circ = 128^\circ

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