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san4es73 [151]
3 years ago
12

Am i right 5TH GRADE MATH THANKS!​

Mathematics
2 answers:
Phantasy [73]3 years ago
7 0

Answer:

Yes you are correct!

Step-by-step explanation:

1. Add 7.06 + 0.85 just using normal addition.

2. You'll get 7.91

3. you can check your answer using a calculator and you'll see you got it correct

Genrish500 [490]3 years ago
6 0

Answer:

Step-by-step explanation:

the answer is 7.9

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Lyle bought a baseball card for $800. If the value of the card decreases by 1.5% each year, find the value of the card after 12
allsm [11]

Answer:

FV= $669.11

Step-by-step explanation:

Giving the following information:

Purchase price (PV)= $800

Decrease value (d)= 1.5% per year

Number of periods (n)= 12 years

<u>To calculate the value of the card after 12 years, we need to use the following formula:</u>

FV= PV / (1 + d)^n

FV= 800 / (1.015^12)

FV= $669.11

6 0
3 years ago
Which graph shows the line y=35x−3?
elena-s [515]

Answer:

the last picture

Step-by-step explanation:

the one where the line hits the -3 mark on the y-axis

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME SOLVE!
Crank

Answer:

F(-6) = <u>2*(-6) + 1</u>

            5*(-6) -2

= <u>-11  </u>

  -32

=   <u>11     </u>

      32

5 0
3 years ago
Read 2 more answers
Pls help branliest if right
Bezzdna [24]

Answer:

sorry I donot know

I wish I could help

7 0
3 years ago
A yogurt company claims that it prints a free yogurt coupon under a randomly selected 20% of its lids. A loyal customer purchase
Alona [7]

Answer:

The customer can conclude that the company's claim is correct

Step-by-step explanation:

The percentage of lids that has a free yogurt coupon = 20%

The number of cups a loyal customer purchases = 85 yogurt cups

The number of cups that contained a coupon = 12 (14.1%)

The confidence interval performed = 99% confidence interval for the proportion of yogurt cups containing coupon codes

The interval obtained = (0.044, 0.238)

Therefore, the range of proportion within which the true proportion exists is 0.044 < \hat p < 0.238

The range of percentage within which the true percentage exist is therefore;

0.044 × 100 = 4.4%  < \hat p × 100 < 0.238 × 100 = 23.8%

Given that the possible true percentage of lids that has a coupon is between 4.4% and 23.8% at 99% confidence level, the customer can conclude that only 12 of his yogurt cup contained coupon by chance and that the company's claim is correct.

4 0
3 years ago
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