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Anna71 [15]
3 years ago
12

R(x) = -13.85x2 + 1,660x C(x) = 55,400 – 279x

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

What am I suppose to do?

Step-by-step explanation:

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I don't get it and it's too confusing
Gwar [14]
10x-3(x-6)=-(x-1)
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10x -3x +18 = -x + 1
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7 x +18 = -x +1
then you leave of when one side of x
6 x +18= +1
use opposite operation on the side with the x and do the same equation to the other side
6 x = -17
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3 0
3 years ago
Which statements are true? Select three options.<br><br> You can use for reference ;)
Dovator [93]
The answers are A,C,&E
3 0
2 years ago
Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an
Natasha_Volkova [10]

Answer:

The volume of the solid is 243\sqrt{2} \ \pi

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0  ≤ ρ²   ≤   81

0  ≤ ρ   ≤  9

The intersection that takes place in the sphere and the cone is:

x^2 +y^2 ( \sqrt{x^2 +y^2 })^2  = 81

2(x^2 + y^2) =81

x^2 +y^2 = \dfrac{81}{2}

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

z = \sqrt{x^2+y^2}

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; \dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}

Thus, volume: V  = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4}  \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho   ^2 \ sin \phi \ d\rho \   d \theta \  d \phi

V  = \int \limits^{\pi/2}_{\pi/4} \ sin \phi  \ d \phi  \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho   ^2 d\rho

V = \bigg [-cos \phi  \bigg]^{\pi/2}_{\pi/4}  \bigg [\theta  \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3}  \bigg ]^{9}_{0}

V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]

V = 243\sqrt{2} \ \pi

4 0
3 years ago
How do you do this i totaly forgot.
vagabundo [1.1K]

Step-by-step explanation:

7^2+8^2=113

Then square root 113 which is 10.63 to 2.d.p

So x=10.63

5 0
3 years ago
25p+1t=51<br>solve for t​
irga5000 [103]

Answer:

t = 51 - 25p

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

25p + 1t = 51

<u>Step 2: Solve for </u><em><u>t</u></em>

  1. [Subtraction Property of Equality] Subtract 25p on both sides:                    1t = 51 - 25p
  2. Simplify:                                                                                                             t = 51 - 25p
5 0
3 years ago
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